x^2-170x+1000=0

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Solution for x^2-170x+1000=0 equation:



x^2-170x+1000=0
a = 1; b = -170; c = +1000;
Δ = b2-4ac
Δ = -1702-4·1·1000
Δ = 24900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{24900}=\sqrt{100*249}=\sqrt{100}*\sqrt{249}=10\sqrt{249}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-170)-10\sqrt{249}}{2*1}=\frac{170-10\sqrt{249}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-170)+10\sqrt{249}}{2*1}=\frac{170+10\sqrt{249}}{2} $

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